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Ohm's Law

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Question

Calculate the resistance of an aluminum cable of length 10km and diameter 2.0mm if the resistivity is 2.7x10^-8 Ohm-meter

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Solution

R=rho x l/a
where, rho =2.7x10^-8ohm m
d=2x10^-3m ==> r=10^-3m ==>A=πr^2=πx10^-6 m^2
l=10x10^3m
therefore, R=2.7x10^-8 X 10x10^3 / πx10^-6 (where π=3.14)
R=85.909 ohm

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