Calculate the resistivity of the material of a wire 2m long , 0.4mm in diameter and having a resistance 2Ω.
A
1×10−7Ω−m
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B
2.5×10−7Ω−m
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C
1.25×10−7Ω−m
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D
2.5×107Ω−m
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Solution
The correct option is C1.25×10−7Ω−m Given: Length of the wire, L =2m Diameter, d=0.4mm=4×10−4m Resistance, R=2Ω Cross section area of wire: =πd22=π×(0.0004)24=1.256×10−7m2 Resistivity, ρ=RAL=2×1.256×10−72 Or, ρ=RAL=1.256×10−7Ω−m