Calculate the resonance energy of N 2 O from the following data- - H f o of N 2 O-134 KJ mol -1Bond energy of N-O-N-O-N- N and O-O bonds are 222- 607- 946 and 498 kJ mol -1 respectively-

N≡ N(g)+12(O=O)→ N=N=O(g) Δ H _ f( N _ 2 O) =[ Δ H _ (N≡ N) + 1 2 Δ H _ (O=O) ] [ Δ H _ (N=O) +Δ H _ (N=N) ] =(946+12× 498) (607+418) =119 ...

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Factors Affecting CFSE and Conclusions

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Question

Calculate the resonance energy of $N_{2} O$ from the following data:
$Δ H_{f}^{o}$ of $N_{2} O = 134 K J {m o l}^{- 1}$
Bond energy of $N - O, N = O, N \equiv N$ and $O = O$ bonds are $222, 607, 946$ and $498 k J {m o l}^{- 1}$ respectively.

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N_{2} O

△_{f} H^{\circ}

N_{2} O = 82 k J m o l^{- 1}

N = N, N = N, O = O

N = O

946, 418, 498

607 k J m o l^{- 1}

Δ H_{f}^{o}

N_{2} O

82 k J / m o l

N_{2}, N = N, O = O

N = O

946, 418, 498

607 k J / m o l

N_{2} O

N_{2} O

(Δ H_{f}^{o}

N_{2} O = 82 k J m o l^{- 1})

N_{2} O

Δ H_{f}

N_{2} O = 82 k J {m o l}^{- 1}

N \equiv N

N \equiv N

O \equiv O

N \equiv O

K J {m o l}^{- 1}

N_{2} O

Δ H_{f}^{\circ}

N_{2} O = 82 k J m o l e^{- 1}

N \equiv N

N = N

O = O

N = O

m o l e^{- 1}

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