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Question

Calculate the resonance energy of N2O from the following data:
fHo of N2O=82 kJ mol1,
NN, 946 kJ mol1; N=N, 418 kJ mol1;
O=O, 498 kJ mol1; N=O,607 kJ mol1

A
88 kJ mol1
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B
98 kJ mol1
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C
78 kJ mol1
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D
78 kJ mol1
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Solution

The correct option is A 88 kJ mol1
Given-
B.E.NN=946 kJ mol1
B.E.O=O=498 kJ mol1
B.E.N=N=418 kJ mol1
B.E.N=O=607 kJ mol1
Formation of N2O
NN(g)+12 O=O(g)N=NO
Ho(cal)=[B.E.NN+1/2 B.E.O=O][B.E.N=N+B.EN=O]
=[946+12(498)[418+607]kJ mol1=170 kJ mol1
[946+12(498)][418+607]kJ mol1=170 kJ mol1
Ho(cal) comes out to be 170 kJ mol1

We know,
Resonance energy =fHo(obs)fHo(cal)

Putting all the values,
=82170=88 kJ mol1
hence, Resonance energy =88 kJ mol1


Theory:

Resonance Energy:

The difference in the energy of the most stable resonating structure and the energy of the actual molecule.

Determination of resonance energy:

For compounds exhibiting resonance
Considerable difference between the calculated and the experimentally determined ΔHo. This occurs due to stabilization by resonance and is measured as Resonance Energy.

Resonance energy =fHo(obs)fHo(cal)

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