Calculate the rms speed of nitrogen at STP pressure - 1 atm and temperature -0- C - The density of nitrogen in these conditions is 1-25 kg m -3-A- 490 m - sB- 510 m - sC- 410 m - sD- 370 m - s

The correct option is A 490 m/s At STP, the pressure is 1.0 × 10^5 N m^ 2. The rms speed is v_rms = √(3p/ρ) = √(3 × 10^5 Nm^ 2/1.25 kg m 3) = 490 ms^ 1. ...

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Standard XII

Physics

RMS and KE Expressions

Calculate the...

Question

Calculate the rms speed of nitrogen at STP (pressure = 1 atm and temperature = $0^{\circ} C$ ). The density of nitrogen in these conditions is $1.25 k g m^{- 3}$ .

490 m/s

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510 m/s

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410 m/s

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370 m/s

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Solution

The correct option is A
490 m/s

At STP, the pressure is $1.0 \times 10^{5} N m^{- 2}$ . The rms speed is

$v_{r m s} = \sqrt{\frac{3 p}{ρ}}$

$= \sqrt{\frac{3 \times 10^{5} N m^{- 2}}{1.25 k g m - 3}}$

$= 490 m s^{- 1}$ .

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Calculate the rms speed of nitrogen at STP (pressure = 1 atm and temperature = 0∘C). The density of nitrogen in these conditions is 1.25 kg m−3.

The correct option is A 490 m/s At STP, the pressure is 1.0×105 N m−2. The rms speed is vrms=√3pρ =√3×105Nm−21.25 kg m−3 =490 ms−1.

Calculate the rms speed of nitrogen at STP (pressure = 1 atm and temperature = $0^{\circ} C$ ). The density of nitrogen in these conditions is $1.25 k g m^{- 3}$ .

The correct option is A
490 m/s

At STP, the pressure is $1.0 \times 10^{5} N m^{- 2}$ . The rms speed is

$v_{r m s} = \sqrt{\frac{3 p}{ρ}}$

$= \sqrt{\frac{3 \times 10^{5} N m^{- 2}}{1.25 k g m - 3}}$

$= 490 m s^{- 1}$ .