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Relating Translational KE and T

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Question

Calculate the root mean square speed of ozone kept in a closed vessel at $20^{o} C$ and 82 cm Hg pressure.

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Solution

$U_{r . m . s} = \sqrt{\frac{3 R T}{M}}$
given $T = 20^{o} C = 20 + 273 = 293 K$
$R = 8.314 \times 10^{7}$ erg/degree/mol
$M (o f O_{3}) = 48$
$U_{r . m . s} = \sqrt{\frac{3 \times 8.314 \times 10^{7} \times 293}{48}}$
$= 3.9 \times 10^{4}$ cm/sec

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