Question

Calculate the root mean square velocity of ozone kept in a closed vessel at ${20}^{\circ }C$ and 82 $cmHg$ pressure. If the value is $39\times {10}^{-x}$, then what is the value of $x$?

Answer 1

$V_{rms}=\sqrt{\frac{3RT}{M}}$

For ozone,

$V_{rms}=\sqrt{\frac{3\times 8.314\times 293}{48\times {10}^{-3}}}=0.3901=39\times {10}^{-2}m{s}^{-1}$

Thus $\text{x}$ is 2