Question

Calculate the $\%$ s-character in the lone pair electron of $N{H}_3$, where the percentage s-character of bond pair is $22\%$ in each $N-H$ bond.

• A. $60\%$
• B. $25\%$
• C. $44\%$
• D. $34\%$

Answer 1

Answer: (D)

$34\%$

The hybridisation of $N=s{p}^3$

$\%s-character$ in N-H bond $=22\%$

Total $\%s-character$ due to N-H bond $=22\times 3=66\%$

$\%s$ character in lone pair of electron $=100-66\%=34$

Hence, option D is correct.