Question

Calculate the shortest wavelength of the spectral lines emitted in Balmer series.[Given Rydberg constant, R=${10}^7{m}^{-l}$]

Answer 1

As per Balmer series, wavelength is given by :

$\frac{1}{\lambda }=R[\frac{1}{2^2}-\frac{1}{n^2}]$

Where, n = 3, 4, 5

For shortest wavelength, n = $\infty$

So, $\frac{1}{\lambda }=R[\frac{1}{2^2}-\frac{1}{{\infty }^2}]$

$\frac{1}{\lambda }={10}^7\left[\frac{1}{4}\right]$

$\lambda =4\times {10}^{-7}m$