Question

Calculate the solubility of carbon dioxide in water at $0^{\circ }C$ and a pressure of 3.0 atm. The solubility of carbon dioxide is 3.48 g/L in water at $0^{\circ }C$ and 1.00 atm.

• A. 12.22 g/L
• B. 10.44 g/L
• C. 5.22 g/L
• D. 1.16 g/L

Answer 1

The correct option is B 10.44 g/L

The solubility of carbon dioxide gas is proportional to the pressure of the gas above the liquid.
$P_1=1atm\text{Solubility},S_1=3.48g/L{P}_2=3atm{S}_2=?$

From Henry's law,
$P_{gas}=K_H{X}_{gas}$
where, $X_{gas}=\text{mole fraction of gas in liquid}$
$P_{gas}\text{is the partial pressure of gas over liquid surface}$
$K_H$ is constant at same temperature
So,
$\text{Solubility}\propto \text{pressure}$

$\frac{S_1}{S_2}=\frac{P_1}{P_2}\Rightarrow \frac{3.48g/L}{S_2}=\frac{1}{3}$
$\Rightarrow S_2\text{(solubility at 3 atm) =}\frac{3}{1}\times 3.48$
$=10.44g/L$