Question

Calculate the specific heat capacity of oil when $5040J$ of heat energy is required to raise the temperature of $60$g of oil by $40$K.

• A. $2500J{kg}^{-1}{K}^{-1}$
• B. $2100J{kg}^{-1}{K}^{-1}$
• C. $1500J{kg}^{-1}{K}^{-1}$
• D. $2700J{kg}^{-1}{K}^{-1}$

Answer 1

The correct option is B $2100J{kg}^{-1}{K}^{-1}$

Given: heat energy $\left(Q\right)=5040$ J, mass = $60$ g =$0.06$ kg, Rise in temperature $\Delta t=10K$
Specific heat capacity of oil = Heat energy(Q)/Mass (m) x Rise in temperature $\Delta t$
$=5040J/(0.06kg\times 40K)$
$2100J{kg}^{-1}{K}^{-1}$