Calculate the speed of sound in oxygen from the following data- The mass of 22-4 litre of oxygen at STP T -273 K- and -p -1-0 - 105 Nm -2 is 32 g- the molar heat capacity of oxygen at constant volume is C v -2-5 R and that at constant pressure is C p -3-5 R-

Given that: ρ =1.0 × 10^ 5N/m^2, t =273 K, M =32 g =32 × 10^ 3kg V =22.4 litre =22.4 × 10^ 3m^3 C/C_y=r=3.5/2.5=1.4 V =r ρ/ρ=1.4 × 1.0 × 10^5/(32/22.4) =310 m/s ...

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Standard XII

Chemistry

Relating Translational KE and T

Calculate the...

Question

Calculate the speed of sound in oxygen from the following data. The mass of 22.4 litre of oxygen at STP (T = 273 K and $p = 1.0 \times 10^{5} N m^{- 2})$ is 32 g, the molar heat capacity of oxygen at constant volume is $C_{v} = 2.5$ R and that at constant pressure is $C_{p} = 3.5 R$ .

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Solution

Given that: $ρ = 1.0 \times 10^{- 5} N / m^{2},$

t =273 K,

$M = 32 g = 32 \times 10^{- 3} k g$

V =22.4 litre

$= 22.4 \times 10^{- 3} m^{3}$

$\frac{C}{C_{y}} = r = \frac{3.5}{2.5} = 1.4$

$V = \frac{r ρ}{ρ} = \frac{1.4 \times 1.0 \times 10^{5}}{(\frac{32}{22.4})}$

=310 m/s

(because $ρ = \frac{m}{v})$

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Calculate the speed of sound in oxygen from the following data. The mass of 22.4 litre of oxygen at STP (T = 273 K and p=1.0×105Nm−2) is 32 g, the molar heat capacity of oxygen at constant volume is Cv=2.5 R and that at constant pressure is Cp=3.5R.

Given that: ρ=1.0×10−5N/m2, t =273 K, M=32g=32×10−3kg V =22.4 litre =22.4×10−3m3 CCy=r=3.52.5=1.4 V=rρρ=1.4×1.0×105(3222.4) =310 m/s (because ρ=mv)

Calculate the speed of sound in oxygen from the following data. The mass of 22.4 litre of oxygen at STP (T = 273 K and $p = 1.0 \times 10^{5} N m^{- 2})$ is 32 g, the molar heat capacity of oxygen at constant volume is $C_{v} = 2.5$ R and that at constant pressure is $C_{p} = 3.5 R$ .