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Quantum Numbers

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Question

Calculate the spin-only magnetic moment of Fe.[Atomic number of iron $= 26$ ].

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Solution

Atomic number of iron $= 26$ .
The electronic configuration of iron is $[A r] 3 d^{6} 4 s^{2}$ . There are 4 unpaired electrons in the valence shell of iron.
The spin-only magnetic moment of $F e$ is
$μ = \sqrt{n (n + 2)}$
$μ = \sqrt{4 (4 + 2)} = 4.89$ B.M

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