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Question

Calculate the standard cell potentials of galvanic cell in which the following reactions take place :

(i) 2Cr(s)+3Cd2+(aq)2Cr3+(aq)+3Cd

(ii) Fe2+(aq)+Ag+(aq)Fe3+(aq)+Ag(s)

Calculate the ΔrG and equilibrium constant for the reactions

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Solution

Given Ecell Cr3+Cr=0.74Vi Ecell (Cd2+Cd)=0.40V

(a) Calculation of standard cell potential (E)Ecell =EcathodeEanode
=(0.40)(0.74)=+0.34V
Ecell =+0.34V

(b) Calculation of ΔrG
ΔrG=nFEcell=(6 mol)×(96500C mol1)×(0.34 V)=196860CV=196860 J=196.86 kJΔrG=196.86 kJ

(c) Calculation of equilibrium constant (Kc)
ΔrG=2.303 RT log Kclog Kc=ΔrG2.303RT=()(196860J)2.303×(8.314 JK1)×(298 K)=34.501Kc=Antilog(34.501)=3.17×1034Kc=3.17×1034

(ii)

Given Ecell(Ag+Ag)=0.80V Ecell(Fe3+Fe2+)=0.77V

(a) Calculation of standard cell potential (E)

Ecell=EcathodeEanode

=(0.80)(0.77)V=0.03V

Ecell=+0.03V

(b) Calculation of ΔrG

ΔrG=nFEcell

= - (1 mol)×(96500 Cmol)×(0.03V)

ΔrG=2.895 kJ

(c) Calculation of equilibrium constant (KC)

ΔrG=2.303 RT log Kc

log Kc=ΔrG2.303RT

=()(2895 J)2.303×(8.314 JK1)×(298 K)=0.5074

KC= Antilog (0.5074) = 3.22

Kc=3.22


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