Calculate the Standard Free Energy Change at 25 degrees celsius given the Equilibrium constant of 1.3 x 10^4.

+23.4 kJ

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- 3.22 x 10^4 kJ

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-23,400 kJ

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-23.4 kJ

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+23,400 kJ

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Solution

The correct option is D -23.4 kJ
The temperature is 25 deg C or 298 K.
$Δ G^{o} = - R T l n K = - 8.314 \times 298 \times l n 1.3 \times 10^{4} = - 23469 J = - 23.4 k J$
Hence, the standard free energy change is -23.4 kJ

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