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Gibbs Free Energy & Spontaneity

Calculate the...

Question

Calculate the standard free energy change for the combustion of glucose at $298 K$ , using the given data.
$C_{6} H_{12} O_{6} + 6 O_{2} (g) ⟶ 6 {C O}_{2} (g) + 6 H_{2} O$
$Δ H^{o} = - 2820 k J {m o l}^{- 1}; Δ S^{o} = 210 J K^{- 1} {m o l}^{- 1}$

A

- 1882.58 k J {m o l}^{- 1}

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B

- 2882.58 k J {m o l}^{- 1}

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C

- 3882.58 k J {m o l}^{- 1}

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D

- 4882.58 k J {m o l}^{- 1}

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Solution

The correct option is C $- 2882.58 k J {m o l}^{- 1}$
For standard free energy change we have
$Δ G = Δ H - T * Δ S$
$Δ G = - 2820000 - 298 * 210 = - 2882580 J m o l^{- 1}$
$Δ G = - 2882.58 K J m o l^{- 1}$

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Similar questions

{Δ H}_{f}^{o}

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