Calculate the standard potential for the reaction- Hg2Cl2 - Cl2- 2Hg- - 4Cl-Given- Hg2Cl2 - 2e- 2Hg - 2Cl- E- - 0-270 volt Hg22- 2Hg2- - 2e- E- - -0-92 volt 2Hg - Hg22- - 2e- E- - -0-79 volt Cl2 - 2e- 2Cl- E- - 1-36 volt-

We can write all the equations with their G values. Hg_2Cl_2+2e^ ⟶ 2Hg+2Cl^ ; G^∘= nFE^∘_cell=–52110J… (1) Hg^2_2⟶ 2Hg^2++2e^ ; G^∘=177560J… ...

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Question

Calculate the standard potential for the reaction,
$H g_{2} C l_{2} + C l_{2} \to 2 H g^{+} + 4 C l^{-}$
Given:
$H g_{2} C l_{2} + 2 e^{-} \to 2 H g + 2 C l^{-}; E^{\circ} = 0.270 v o l t$
$H g_{2}^{2 +} \to 2 H g^{2 +} + 2 e^{-}; E^{\circ} = - 0.92 v o l t$
$2 H g \to H g_{2}^{2 +} + 2 e^{-}; E^{\circ} = - 0.79 v o l t$
$C l_{2} + 2 e^{-} \to 2 C l^{-}; E^{\circ} = 1.36 v o l t$ .

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