Calculate the strength of $10$ volume solution of hydrogen peroxide.

3 %

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 3 %
$10$ Volume of $H_{2} O_{2}$ means that $1 L$ at $H_{2} O_{2}$ at STP gives $10 L$ of oxygen at STP

$2 H_{2} O_{2} (l) ⟶ O_{2} (g) + H_{2} O (l)$

$2 \times 34 g$ $22.4 L$ at STP
$68 g$

$\Rightarrow 22.7 L$ of oxygen produced from $68 g m H_{2} O_{2}$

$10 L$ of $O_{2}$ at STP is produced from $\frac{68 \times 10}{22.4} g = 30.36 g \approx 30 g H_{2} O$

The strength of $10$ Volume $H_{2} O_{2} = 30 g / L$

$3 %$ $H_{2} O_{2}$ solution

Hence, the correct option is $A$

Suggest Corrections

Similar questions

There is a sample of 10 volume of hydrogen peroxide solution. Calculate its strength

8.5 g

280 m L

H_{2} O_{2}

34 g

1120 m L

H_{2} O_{2}

10

Join BYJU'S Learning Program