Calculate the strength of 5 volume $H_{2} O_{2}$ Solution

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Solution

$5$ volume $H_{2} O_{2}$ solution means that hydrogen peroxide contained in 1 volume of this solution will decompose to give $5$ volumes of oxygen at STP i.e. if 1 L of this solution is taken, then 5 L of oxygen can be produced from this at STP chemical equation for the decomposition of $H_{2} O_{2}$ is:
$2 H_{2} O_{2} (l) \to O_{2} (g) + 2 H_{2} O (l)$

it shows that 68g $H_{2} O_{2}$ gives $22.4 L$ of $O_{2}$ at STP

So 5L oxygen will be obtained from:
$\frac{68 g \times 5 L}{22.4 L} = \frac{3400}{224} g H_{2} O_{2} = 15 g H_{2} O_{2}$

i.e 15 g $H_{2} O_{2}$ dissolved in 1L solution will give 5L oxygen or 1.5 g $H_{2} O_{2} / 100 m L$ solution will give $500 m L$ oxygen. Thus $15 g / L$
or $1.5 %$ solution is known as 5 volume solution of $H_{2} O_{2}$

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