Calculate the stress developed in a metal wire when its strained by 30 %.Given Youngs modulus of material is 200Gpa.

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Solution

$s t r a i n d e v e l o p e d = 30 % = \frac{30}{100} = 0.3 Y = 200 \times 10^{9} s t r e s s = Y \times s t r a i n = 200 \times 10^{9} \times 0.3 = 6 \times 10^{10} p a$

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Calculate the stress developed in a metal wire when its strained by 30 %.Given Youngs modulus of material is 200Gpa.

strain developed = 30% = 30100 = 0.3Y = 200×109stress = Y×strain =200×109×0.3 = 6×1010 pa

$s t r a i n d e v e l o p e d = 30 % = \frac{30}{100} = 0.3 Y = 200 \times 10^{9} s t r e s s = Y \times s t r a i n = 200 \times 10^{9} \times 0.3 = 6 \times 10^{10} p a$