Question

Calculate the sum of angles of a polygon having $10$ sides.

• A. ${960}^{\circ }$
• B. ${1440}^{\circ }$
• C. ${900}^{\circ }$
• D. ${720}^{\circ }$

Answer 1

The correct option is B ${1440}^{\circ }$

Sum of interior angles of a polygon = ${180}^o(n-2)$
When $n=10$,
Sum of interior angles of a polygon = ${180}^o(n-2)={180}^o(10-2)={1440}^o$