Question

Calculate the sum of angles of a polygon having $12$ sides.

• A. ${900}^{\circ }$
• B. ${720}^{\circ }$
• C. ${1800}^{\circ }$
• D. ${1440}^{\circ }$

Answer 1

Answer: (C)

${1800}^{\circ }$

Sum of interior angles of a polygon = ${180}^o(n-2)$
When $n=12$
Sum of interior angles of a polygon = ${180}^o(n-2)={180}^o(12-2)={1800}^o$