Calculate the sum of first 30 terms of the A.P.−2,−5,−8,−11....
A
−1165
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B
−1265
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C
−1365
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D
−1465
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Solution
The correct option is B−1365 First term of the given arithmetic series = -2 Second term of the given arithmetic series = -5 Third term of the given arithmetic series = -8 Fourth term of the given arithmetic series = -11 Now, Second term - First term = -5 - (-2) = -3 Third term - Second term = -8 - (-5) = -3 Therefore, common difference of the given arithmetic series is -3. The number of terms of the given A. P. series (n) = 30 We know that the sum of first n terms of the Arithmetic Progress, whose first term = a and common difference = d is Sn=(n/2)[2a+(n−1)d]Sn=n2[2a+(n−1)d]