Question

Calculate the sum of interior angles of a polygon having $25$ sides.

• A. ${4140}^{\circ }$
• B. ${4330}^{\circ }$
• C. ${4680}^{\circ }$
• D. ${4900}^{\circ }$

Answer 1

The correct option is A ${4140}^{\circ }$

Sum of interior angles of a polygon = ${180}^o(n-2)$

where, $n=$ number of sides

When $n=25$
Sum of interior angles of a polygon = ${180}^o(n-2)={180}^o(25-2)={4140}^o$