Calculate the sum of the series 14+11+8+5+...+−82.
A
1122
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B
1022
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C
−1022
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D
−1122
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Solution
The correct option is B−1122 First term = a=14 last term, l=−82 an=−82 Common difference = -3 an=a+(n−1)d −82=14+(n−1)(−3) −82−14−3=−3n −99=−3n n=33 Sn=n2[a+l] S33=332[14+(−82)] S33=16.5[−68] S33=−1122