Question

Calculate the surface area in (sq m) of a catalyst that adsorbs ${10}^{3}c{m}^3$ of nitrogen reduced to STP per gram in order to form the monolayer. The effective area ($in{m}^2$) occupied by $N_2$ molecule on the surface is: ( surface area of $N_2=1.62\times {10}^{-15}c{m}^2$)

Answer 1

According to the given data,

Number of $N_2$ molecules

$=\frac{Volume\left(ml\right)\times N_A}{VolumeatSTP\left(inml\right)}$

$=\frac{{10}^3\times 6.023\times {10}^{23}}{22400}=2.69\times {10}^{22}$.

Total area covered by $N_2=2.69\times {10}^{22}\times 1.62\times {10}^{-15}$ $=435.5\times {10}^{5}c{m}^2=4355m^2$.