Question

Calculate The Temperature Of 40 Mol Of A Gas Occupying 5 dm3 At 3.32 Bar.

Answer 1

Explanation for Correct answer:-

Given Data:

No. of moles = n = 40

Pressure = P = 3.32 bar

Volume = V = $5{\mathrm{dm}}^3$

R = Gas Constant $=0.0821\mathrm{liter}\mathrm{atm}{\mathrm{mol}}^{-1}{\mathrm{K}}^{-1}$

Applying Ideal Gas equation:

We know that,

PV = nRT

So, $\mathrm{T}=\frac{\mathrm{PV}}{\mathrm{nR}}$

Putting the values of P, n, R, and V, we get,

T = $\frac{3.32\mathrm{x}5}{4\mathrm{x}0.0821}K$

T = 50K

Therefore, the temperature is 50K.