You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Molecular Speeds - Vrms, Vavg, Vmps

Calculate the...

Question

Calculate the temperatures ( $T_{1}$ & $T_{2}$ ) (in $K$ ) at which the molecules of the first two members of the homologous series $C_{n} H_{2 n + 2}$ will have the same $r m s$ speed as $C O_{2}$ gas has 770 $K$ .
Then, $T_{1} + T_{2} = ?$

Open in App

Solution

The first two members of homologous series $C_{n} H_{2 n + 2}$ are $C H_{4}$ and $C_{2} H_{6}$ having molar mass 16 and 30 respectively.
For $C H_{4} : u_{r m s} = \sqrt{\frac{3 \times R \times T}{16}} = \sqrt{\frac{3 \times R \times 770}{44}}$
$T = 280 K$
For $C_{2} H_{6} : u_{r m s} \sqrt{\frac{3 \times R \times T}{30}} = \sqrt{\frac{3 \times R \times 770}{44}}$
$T = 525 K$
so $T_{1} + T_{2} = 280 + 525 = 805 K$

Suggest Corrections

Similar questions

Q. Calculate the temperature values at which the molecules of the first two members of the homologous series,

C_{n} H_{2 n + 2}

will have the same rms speed as

C O_{2}

gas at 770 K. The normal b.p. of n

-

butane is 273 K. Assuming ideal gas behavior of n

-

butane up to this temperature, calculate the mean velocity and the most probable velocity of its molecules at this temperature.

Q. Calculate the temperature values at which the molecules of the first two members of the homologous
series,

C_{n} H_{2 n + 2}

will have the same rms speed as

C O_{2}

gas at 770

K

. The normal b.p. of

n

- butane is 273

K

This question has multiple answers.

Q. The average speed at temperature

T_{1}

and most probable speed at

T_{2}

C O_{2}

gas is

2.8282 m / s e c

. Calculate the values of

T_{1}

and

T_{2}

The average speed at $T_{1} K$ and most probable speed at $T_{2} K$ of $C O_{2}$ gas is $9 \times 10^{4}$ cm/sec. The values of $T_{1}$ and $T_{2}$ are

Q. A box contains

N

molecules of a perfect gas at temperature

T_{1}

and pressure

P_{1}

. The number of molecules in the box is doubled keeping the total kinetic energy of the gas same as before. If the new pressure and temperature are

P_{2}

are

T_{2}

respectively, then

Join BYJU'S Learning Program

Calculate the temperatures (T1 & T2) (in K) at which the molecules of the first two members of the homologous series CnH2n+2 will have the same rms speed as CO2 gas has 770 K.Then, T1+T2=?

The first two members of homologous series CnH2n+2 are CH4 and C2H6 having molar mass 16 and 30 respectively.For CH4:urms=√3×R×T16=√3×R×77044T=280KFor C2H6:urms√3×R×T30=√3×R×77044T=525Kso T1+T2=280+525=805K

Calculate the temperatures ( $T_{1}$ & $T_{2}$ ) (in $K$ ) at which the molecules of the first two members of the homologous series $C_{n} H_{2 n + 2}$ will have the same $r m s$ speed as $C O_{2}$ gas has 770 $K$ .
Then, $T_{1} + T_{2} = ?$