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Question

Calculate the temperatures (T1 & T2) (in K) at which the molecules of the first two members of the homologous series CnH2n+2 will have the same rms speed as CO2 gas has 770 K.
Then, T1+T2=?

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Solution

The first two members of homologous series CnH2n+2 are CH4 and C2H6 having molar mass 16 and 30 respectively.
For CH4:urms=3×R×T16=3×R×77044
T=280K
For C2H6:urms3×R×T30=3×R×77044
T=525K
so T1+T2=280+525=805K

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