Question

Calculate the tension in the massless string. A block of mass m is suspended by string as shown above.

• A. $mgcos\theta$
• B. $2mgcos\theta$
• C. $mgsin\theta$
• D. $\frac{1}{2}mgsin\theta$
• E. $\frac{mg}{2sin\theta }$

Answer 1

The correct option is E $\frac{mg}{2sin\theta }$

Let the tension in the string be $T$.

As the block is in equilibrium, thus $F_{net}=0$

$\therefore$ $2Tsin\theta -mg=0$ $⟹T=\frac{mg}{2sin\theta }$