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Latent Heat

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Question

Calculate the thermal capacity of $1.5 k g$ of water

A

1500 J^{o} C^{- 1}

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B

4200 J^{o} C^{- 1}

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C

6300 J^{o} C^{- 1}

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D

8400 J^{o} C^{- 1}

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Solution

The correct option is D $6300 J^{o} C^{- 1}$
Thermal heat capacity $= m c$
specific heat of water $c = 4200 J / k g^{o} C$
Thermal heat capacity = $1.5 \times 4200 = 6300 J^{o} C^{- 1}$

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