You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Potential Energy - External Viewpoint

Calculate the...

Question

Calculate the time for which a motor pump of 10 HP and efficiency 80% must be switched on, so as to pump 20m^3 of water through a vertical height of 20m. (Density of water=1000kgm^-3, g=10ms^-2, 1HP=750W)

Open in App

Solution

Dear student

Power of motor pump= 10 HP
= 80/100* 10* 750
= 6000 Watt

We know,
Work done= pt
mgh= 6000 t
( mass= density* volume)

20100010* 20 = 6000* t
t = 20,000*20,000/ 6000
= 666.67 sec

Regards

Suggest Corrections

Similar questions

Q. A water pump raises

50

litres of water through a height of

25 m

5 s

. Calculate the power which the pump supplies. (Take

g = 10 N

k g^{- 1}

and density of water

= 1000 k g m^{- 3}

)

A water pump raises 50 litre of water through a height of 25 m in 5 s. Calculate the power of the pump required.(Take g=10 N $k g^{- 1}$ and density of water=1000 kg $m^{- 3}$ .

Q. A

1.0

HP motor pumps out water from a well of depth

20 m

and fills a water tank of volume

2238

litres at a height of

10 m

from the ground. The running time of the motor to fill the empty water tank is

(g = 10 m s^{- 2})

Q. A

1.0

hp motor pumps out water from a well of depth

20 m

and fills a water tank of volume

2238

liters at a height of

10 m

from the ground. The running time of the motor to fill the empty water tank is

(g = 10 {m s}^{- 2})

Q. A

750 W

motor drives a pump which lifts

300

litres of water per minute to a height of

6

meters. The efficiency of the motors is nearly (take acceleration due to gravity to be

10 m / s^{2}

)

Join BYJU'S Learning Program

Calculate the time for which a motor pump of 10 HP and efficiency 80% must be switched on, so as to pump 20m^3 of water through a vertical height of 20m. (Density of water=1000kgm^-3, g=10ms^-2, 1HP=750W)

Dear student Power of motor pump= 10 HP = 80/100* 10* 750 = 6000 Watt We know, Work done= p*t mgh= 6000* t ( mass= density* volume) 20*1000*10* 20 = 6000* t t = 20,000*20,000/ 6000 = 666.67 sec Regards

Dear student

Power of motor pump= 10 HP
= 80/100* 10* 750
= 6000 Watt

We know,
Work done= pt
mgh= 6000 t
( mass= density* volume)

20100010* 20 = 6000* t
t = 20,000*20,000/ 6000
= 666.67 sec

Regards