Question

Calculate the torque developed by an airplane engine whose output is $2000HP$ at an angular velocity of $2400rev/min$ ?

Answer 1

$\omega =2\pi \left(2400/60\right)=80\pi /rad/s$
Work done by torque $=\left(torque\right)\times \left(angulardisplacement\right)$
$Power=$ work done per sec $=\tau \frac{△\theta }{△t}$
$Power=\tau \omega \Rightarrow \tau =\frac{2000\times 746}{80\pi }=5937Nm$.