Question

calculate the torque developed by an airplane engine whose output is $2000$ HP at an angular velocity of $2400$ rev/min.

Answer 1

since

$\omega =2\pi \left(2400/60\right)=80\pi rad/s$

Work done by torque =(torque)$\times$ (angular displacement)

Power=work done per sec $=\tau \left(\Delta \Theta /\Delta t\right)$

Power n$=\tau \omega$

$\tau =\frac{2000\times 746}{80\pi }=5934Nm$