Question

Calculate the torque developed by an airplane engine whose output is $3200\text{HP}$ at an angular velocity of $2400\text{rev/min}$. $(1\text{HP}=746\text{J/s})$

• A. $9498\text{N-m}$
• B. $1273\text{N-m}$
• C. $2984\text{N-m}$
• D. $5000\text{N-m}$

Answer 1

The correct option is A $9498\text{N-m}$

Given, power of engine $\left(P\right)=3200\text{HP}$
Number of rotation $\left(N\right)=2400\text{rev/min}$
or angular velocity $\omega =\frac{2\pi N}{60}=2\pi \times \frac{2400}{60}=80\pi \text{rad/s}$
Now, we know that power $P=\tau \omega$
$\Rightarrow \tau =\frac{P}{\omega }=\frac{3200\times 746}{80\pi }=9498\text{N-m}$