Calculate the torque developed (in Nm) by an airplane engine whose output is $2000 H P$ at an angular velocity of $2400 r e v / m i n$ .

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Solution

$ω = 2 π (2400 / 60) = 80 π r a d / s$
Word done by torque = (torque)\times(angular displacement)
Power = work done per sec = $τ \frac{△ θ}{△ t}$
Power = $τ ω \Rightarrow τ = \frac{2000 \times 746 J / s}{80 π r a d / s} = 5937 N m$

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Calculate the torque developed (in Nm) by an airplane engine whose output is 2000 HP at an angular velocity of 2400 rev/min.

ω=2π(2400/60)=80π rad/sWord done by torque = (torque)\times(angular displacement)Power = work done per sec = τ△θ△tPower = τω⇒τ=2000×746J/s80πrad/s=5937 Nm

Calculate the torque developed (in Nm) by an airplane engine whose output is $2000 H P$ at an angular velocity of $2400 r e v / m i n$ .

$ω = 2 π (2400 / 60) = 80 π r a d / s$
Word done by torque = (torque)\times(angular displacement)
Power = work done per sec = $τ \frac{△ θ}{△ t}$
Power = $τ ω \Rightarrow τ = \frac{2000 \times 746 J / s}{80 π r a d / s} = 5937 N m$