Calculate the total ions and charge present in 4.2 gram ofN^3-.
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Solution
Nitrogen-Symbol-N -7(atomic number) N³⁻ ion = 1s²2s²2p⁶ Total number of electrons =10 atomic mass of N=14 14g of N³⁻ ion contains 10NA electrons where NA - Avagadro number so, 1 g of N³⁻ ion =10NA/14 ∴4.2g of N³⁻ ion =4.2x 10NA/14 =3NA