Calculate the total moles of atoms of each element present in 122.5 g of ${K C l O}_{3}$ .

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Solution

Atomic mass of $K C l O_{3}$
Hence $,$ No $.$ of mole of compound $= \frac{G i v e n w e i g h t}{A t o m i c w e i g h t}$
$= \frac{122.5}{122.5} = 1$ mole
Hence $,$ It contains $1$ mole of $K$ atom
$1$ mole of $C l$ atom
and $3$ mole of $0$ atom $.$

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