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Question

Calculate the total n-factor for the reduction half reaction given below:
Fe2(SO4)3FeO+SO2

A
4
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B
8
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C
6
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D
5
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Solution

The correct option is B 8
For the given reaction :
+3Fe2(+6SO4)3(s)+2FeO(s)++4SO2(g)
Reduction :
Fe+3Fe+2
nf=| 32 |×2=2
Reduction :
S+6S+4
nf=| 64 |×3=6
(nf)T=(nf)Fe+(nf)S=2+6=8

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