Calculate the total n-factor for the reduction half reaction given below: Fe2(SO4)3⟶FeO+SO2
A
4
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B
8
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C
6
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D
5
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Solution
The correct option is B 8 For the given reaction : +3Fe2(+6SO4)3(s)⟶+2FeO(s)++4SO2(g)
Reduction : Fe+3⟶Fe+2 nf=|3−2|×2=2
Reduction : S+6⟶S+4 nf=|6−4|×3=6 (nf)T=(nf)Fe+(nf)S=2+6=8