Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

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Solution

Molar mass of dinitrogen (N₂) = 28 g mol^–1

Thus, 1.4 g of

Now, 1 molecule of contains 14 electrons.

Therefore, 3.01 × 10²³ molecules of N₂ contains = 14 × 3.01 × 1023

= 4.214 × 10²³ electrons

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Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

Molar mass of dinitrogen (N2) = 28 g mol–1 Thus, 1.4 g of Now, 1 molecule of contains 14 electrons. Therefore, 3.01 × 1023 molecules of N2 contains = 14 × 3.01 × 1023 = 4.214 × 1023 electrons

Molar mass of dinitrogen (N₂) = 28 g mol^–1

Thus, 1.4 g of

Now, 1 molecule of contains 14 electrons.

Therefore, 3.01 × 10²³ molecules of N₂ contains = 14 × 3.01 × 1023

= 4.214 × 10²³ electrons