Question

Calculate the total number of electrons present in $18$ mL of water.

Answer 1

water density is equal to 1

So 18 ml water= 18 gram water = one mole water

in one molecule of water there are 1o electrons are present

Thus in one mole water there are $6.023\times {10}^{23}$ molecules of water are present

Thus number of electrons in one mole = $10\times 6.023\times {10}^{23}=6.023\times {10}^{24}$ electrons