Calculate the total number of molecules that will possess fractional bond order among the following molecules
$O_{2}^{2 +}, N_{2}^{2 +}, O_{2}^{+}, N O, C O, C O^{+}, O_{2}^{-}, N O^{2 +}, C N^{-}, N O^{2 -}, N_{2}^{-}$

Open in App

Solution

$B o n d o r d e r = \frac{1}{2} \times (b o n d i n g e^{-} - a n t i b o n d i n g e^{-})$

mass molecular configuration molecules

$⩽ 14$ $σ 1 s, σ^{} 1 s, σ 2 s, σ 2 s^{}, π (p_{x} = P_{y}), σ p_{z}, π^{} (p_{x} = P_{y}), σ^{} p_{z}$ N ₂^{2 +}
CO
CO ⁺
CN ⁻
N₂⁻

$> 14$ $σ 1 s, σ^{} 1 s, σ 2 s, σ 2 s^{}, σ p_{z}, π (p_{x} = P_{y}), π^{} (p_{x} = P_{y}), σ^{} p_{z}$ O₂^{2 +}
O₂⁺
NO
O₂⁻
NO ² ⁺
NO ² ⁻

$O_{2}^{+}$ = 2.5, $N O$ =2.5 , $C O^{+}$ =3.5

$O_{2}^{-}$ =1.5, $N O^{2 +}$ =2.5, $N O^{2 -}$ =1.5

$N_{2}^{-}$ = 2.5

Suggest Corrections

Similar questions

Among the following the total no. of species which are paramagnetic

$O_{2}, S_{2}, C N^{-}, N O^{+}, O_{2}^{2 +}, O_{2}^{2 -}, B_{2}, N_{2}^{2 -}, O_{2}^{+}, N O, N O_{2}, N_{2} O$ ___

C N^{-}, N O, O_{2}^{2 -}, O_{2}, N O_{2}, O_{2}^{-}, B_{2}, C_{2}, F_{2}^{-}

N_{2} O, N O, N O_{2}, O_{2}, N O_{2}^{+}, N O^{+}, C O^{+}

(i) O_{2}^{+} (i i) C O (i i i) B_{2} (i v) O_{2}^{-}

(v) N O^{+} (v i) H e_{2}^{+} (v i i) C_{2}^{2 +} (v i i i) C N^{-}

(i x) N_{2}^{-}

2 N_{2} O_{5} ⟶ 4 N O_{2} + O_{2}

N_{2} O_{5} ⇌ N O_{2} + N O_{3}

N O_{2} + N O_{3} ⟶ N O + N O_{2} + O_{2}

N O + N O_{3} ⟶ 2 N O_{2}

Join BYJU'S Learning Program