Question

Calculate the total number of protons in $10$ gms of Calcium Carbonate ($CaC{O}_3$)

Answer 1

First we will find the no. of moles in 10 grams of $CaC{O}_3$3

Molecular mass of $CaC{O}_3$ $=(40+12+16\times 3)=100g/mole$

No. of moles$=\frac{10}{100}=0.1mole$

No. Of protons in one molecule of $CaC{O}_3$ $=(20+6+8\times 3)=50g/mole$

No. of protons in 0.1 mole of $CaC{O}_3$ will be

$=0.1\times 50\times 6.022\times {10}^{23}$

$=3.011\times {10}^{24}$ protons