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Magnetic Moment Examples

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Question

Calculate the total number of unpaired electrons in acoordination compound with magnetic moment of 5.92 B.M.

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Solution

A coordination compound with magnetic moment of 5.92 B.M contains 5 unpaired electrons.
$μ = \sqrt{n (n + 2)} = 5.92$
$n (n + 2) = (5.92)^{2} = 35$
Hence, $n = 5$ .

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Similar questions

If the magnetic moment of a complex compound is 2.8 B.M. Then the number of unpaired electrons in compound is:

The substances which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. Such substances are weakly attracted by the magnetic field. The paramagnetism is expressed in terms of the magnetic moment. The magnetic moment is related to the number of unpaired electrons according to the following relation:

Magnetic moment,

μ = \sqrt{n (n + 2)} B M

n =

number of unpaired electrons.

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stands for Bohr magneton, a unit of the magnetic moment.

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The substances which contain species with unpaired electrons in
their orbitals behave as paramagnetic substances. Such substances
are weakly attracted by the magnetic field. The paramagnetism is
expressed in terms of magnetic moment. The magnetic moment is
related to the number of unpaired electrons according to the
following relation:
Magnetic moment,

μ = \sqrt{n (n + 2)} B M

n =

number of unpaired electrons.

B M

stands for Bohr magneton, a unit of magnetic moment.

1 B M = \frac{e h}{4 π m c} = 9.27 \times 10^{- 24} {A m}^{2}

J T^{- 1}

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