Question

Calculate the total reactance if two inductor of 10mH and 50 mH are connected in series with 10 kHz AC.

Answer 1

Total Reactance is given by

$X=X_1+X_2=\omega (L_1+L_2)$

$⟹X=2\pi f(L_1+L_2)$

$⟹X=2\times {10}^4\times \pi (60\times {10}^{-3})$

$⟹X=3768\Omega =3.768K\Omega$