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Question

Calculate the total surface area of a frustum of cone whose upper base radius is 2m and lower base radius is 4 m and its height is 12 m. (Use π = π).

A
4π(337 + 5) m2
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B
3π(337 + 5) m2
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C
2π(337 + 5) m2
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D
π(337 + 5) m2
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Solution

The correct options are
A 4π(337 + 5) m2
D 2π(337 + 5) m2
Total surface area, SA = (r + R)π(Rr)2+h2+πr2+πR2

R = 4m, r = 2m, h = 12m

SA = (2 + 4)π(42)2+122+π22+π42

= 6π(2)2+122+4π+16π

= 6π4+144+20π

= 6π148+20π

= 4π(337+5) m


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