Calculate the total surface area of frustum cone given below:

4.05

π m^{2}

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5.05

π m^{2}

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6.05

π m^{2}

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7.05

π m^{2}

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Solution

The correct option is C 6.05 $π m^{2}$
Total surface area = $π (R + r) s + π R^{2} + π r^{2}$
$= π (0.2 + 0.1) 20 + π {0.2}^{2} + π {0.1}^{2}$
$= 6 π + 0.04 π + 0.01 π$
= $6.05 π m^{2}$

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Calculate the total surface area of frustum cone given below:

The correct option is C 6.05 πm2Total surface area = π(R+r)s+πR2+πr2=π(0.2+0.1)20+π0.22+π0.12=6π+0.04π+0.01π= 6.05πm2

The correct option is C 6.05 $π m^{2}$
Total surface area = $π (R + r) s + π R^{2} + π r^{2}$
$= π (0.2 + 0.1) 20 + π {0.2}^{2} + π {0.1}^{2}$
$= 6 π + 0.04 π + 0.01 π$
= $6.05 π m^{2}$