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Question

Calculate the H of the reaction

HH|C|ClCl(g)C(s)+2H(g)+2Cl(g)

Bond energy for C-H bond & C-Cl bond are 415KJ and 326KJ respectively.

A

-1482 kJ

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B

1482 kJ

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C

1483 kJ

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D

-1483 kJ

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Solution

The correct option is B

1482 kJ


The enthalpy change can be given by:
H = Sum of bond energies of reactants - sum of bond energies of products
H = [2 × (C - H) + 2(C - Cl)] - 0
H = 2 ×415 + 2 × 326

H = 1482 KJ

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