Calculate the uncertainly is the positive of dust particle with mass equal to 1mg.In uncertainly in velocity is $5.5 \times 10^{- 20} m / s$ .

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Solution

$Δ x \times Δ p = \frac{h}{4 π} Δ x \times m \times Δ v = \frac{h}{4 π} 10^{- 3} \times Δ x \times 5.5 \times 10^{- 26} = \frac{h}{4 π} Δ x = \frac{6.626 \times 10^{- 34}}{4 \times 3.14 \times 10^{- 23} \times 5.5} = 9.58 \times 10^{- 13}$

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Calculate the uncertainly is the positive of dust particle with mass equal to 1mg.In uncertainly in velocity is 5.5×10−20m/s.

Δx×Δp=h4πΔx×m×Δv=h4π10−3×Δx×5.5×10−26=h4πΔx=6.626×10−344×3.14×10−23×5.5=9.58×10−13

Calculate the uncertainly is the positive of dust particle with mass equal to 1mg.In uncertainly in velocity is $5.5 \times 10^{- 20} m / s$ .

$Δ x \times Δ p = \frac{h}{4 π} Δ x \times m \times Δ v = \frac{h}{4 π} 10^{- 3} \times Δ x \times 5.5 \times 10^{- 26} = \frac{h}{4 π} Δ x = \frac{6.626 \times 10^{- 34}}{4 \times 3.14 \times 10^{- 23} \times 5.5} = 9.58 \times 10^{- 13}$