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Question

Calculate the useful work of the reaction Ag(s)+1/2Cl2(g)AgCl(s).
Given E0cl2/Cl=+1.36V, E0Ag|AgCl|Cl=0.22V if PCl2=1 atm and T=298K.

A
110 kJ/mol
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B
220 kJ/mol
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C
55 kJ/mol
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D
1000 kJ/mol
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Solution

The correct option is A 110 kJ/mol
(1) AgCl(s)+eAg(s)+Cl E0=0.22V
(2) 1/2Cl2+eCl E0=1.36V
We get
Ag(s)+1/2Cl2(g)AgCl(s) E0cell=1.14V
ΔG=nEF0=(1)(96500)(1.14)=110kJ/mol

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